Derivative of 8e^x+8x^-1/3

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Derivative of 8e^x+8x^-1/3:


(8*e^x+(8*x^-1)/3)'

(8*e^x)'+((8*x^-1)/3)'

(8)'*e^x+8*(e^x)'+((8*x^-1)/3)'

0*e^x+8*(e^x)'+((8*x^-1)/3)'

0*e^x+8*ln(e)*e^x+((8*x^-1)/3)'

0*e^x+8*e^x+((8*x^-1)/3)'

8*e^x+((8*x^-1)'*3-(8*x^-1*(3)'))/(3^2)

8*e^x+(((8)'*x^-1+8*(x^-1)')*3-(8*x^-1*(3)'))/(3^2)

8*e^x+((0*x^-1+8*(x^-1)')*3-(8*x^-1*(3)'))/(3^2)

8*e^x+((0*x^-1+8*-1*x^(-1-1))*3-(8*x^-1*(3)'))/(3^2)

8*e^x+((0*x^-1+8*(-x^-2))*3-(8*x^-1*(3)'))/(3^2)

8*e^x+(8*(-x^-2)*3-(8*x^-1*(3)'))/(3^2)

8*e^x+(8*(-x^-2)*3-(8*x^-1*0))/(3^2)

8*e^x+(8*x^-2)/3

The calculation above is a derivative of the function f (x)

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